Preparing for the Joint Admissions and Matriculation Board (JAMB) Physics exam can be challenging, especially when you’re unsure about the types of questions that might appear. However, past questions and answers can be a valuable resource in your preparation.
In this article, we have compiled a list of randomly selected JAMB Physics repeated questions, along with their answers, to help you familiarize yourself with the exam pattern and boost your chances of scoring high.
- Why is a silver spoon cooler to touch than a wooden spoon at room temperature? Answer: D (is a better conductor of heat) Explanation: Silver is a better conductor of heat compared to wood. Therefore, when both spoons are at the same room temperature, the silver spoon quickly transfers heat from your hand, making it feel cooler to touch.
- When two objects P and Q are supplied with the same quantity of heat, and the temperature change in P is observed to be twice that of Q, with P having half the mass of Q, what is the ratio of the specific heat of P to Q? Answer: C (1:1) Explanation: The specific heat capacity is defined as the amount of heat energy required to raise the temperature of a unit mass of a substance by 1 degree Celsius. Since P and Q have the same quantity of heat, but P has half the mass of Q, the temperature change will be twice as much in P, resulting in an equal ratio of specific heat between the two objects.
- When a yellow card is observed through a blue glass, how would the card appear? Answer: A (Black) Explanation: When yellow light passes through a blue glass, it absorbs most of the yellow light, leaving only the blue light to be transmitted. Since the card reflects yellow light, it will appear black when observed through a blue glass.
- In a nuclear plant, if the final mass of the products is 6.32×10^-27 kg and the initial mass of the reactant is 6.30×10^-27 kg, what is the energy released in the process? (Given: speed of light in vacuum = 3.0×10^8 m/s, 1eV = 1.6×10^-19 J) Answer: A (11.25 meV) Explanation: The mass-energy equivalence principle (Einstein’s famous equation, E = mc^2) states that energy (E) is equal to mass (m) multiplied by the speed of light squared (c^2). By calculating the change in mass and converting it to energy using the given values, the answer is 11.25 meV.
- A stone with a mass of 1.5 kg is thrown vertically upward with an initial velocity of 42 m/s. What is the potential energy of the stone at the highest point reached? Answer: A (3.15 J) Explanation: Potential energy is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height. At the highest point, the stone has zero kinetic energy, and all the initial energy is converted into potential energy. By substituting the values into the formula, the potential energy is calculated as 3.15 J.
Please note that this is a small sample of the questions provided, and it’s essential to study a broader range of topics and practice extensively to perform well in the JAMB Physics exam.
The questions above cover various topics such as heat transfer, thermodynamics, optics, nuclear physics, and mechanics.
Conclusion
Preparing for JAMB Physics requires a solid understanding of fundamental concepts and regular practice with past questions.
The questions provided here give you a glimpse into the type of questions you might encounter in the exam.
Remember to study the entire syllabus, use additional study materials, and solve as many practice questions as possible to increase your chances of scoring high. Best of luck in your JAMB Physics exam!